Question

I need help with these questions :

(see image )
Answer (b) and 19.
Note : these questions are under projectile.​

Answer 1

Hey There!

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Answer:

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Projectile Motion:

The motion in which a body has constant horizontal component of velocity

but changing vertical component of velocity is called projectile motion. Every projectile body has PROJECTILE MOTION.

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VERTICAL VELOCITY:

The Vertical Velocity will decrease during upward motion and increase during downward motion, by the factor,

`V_f = V_iSin(theta) - gt (Upward Motion)\\\\V_f = V_iSin(theta) + gt (Downward Motion)`

Where,

Vf = final velocity

Vi = initial velocity

Theta θ is the angle at which projectile is fired

g is acceleration due to gravity

t is time

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B) HORIZONTAL VELOCITY:

HORIZONTAL VELOCITY remains constant. According to Newton's 1st Law object in motion stays in motion until a force acts on it. There are no forces acting on a projectile in the horizontal direction (neglecting air resistance), therefore the velocity is constant.

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Question 19:

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DATA:

Angle = θ(theta) = 30

Initial Velocity =
`V_0 = 150 ms^(-1)`

g = 10 m/s^2

Time taken to reach maximum height = T = ?

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SOLUTION:

The time taken by the projectile to reach the maximum height is given by,

`T = (V_0Sin(theta))/(g)\\\\T = (150Sin(30))/(10)\\\\T = (150x0.5)/(10)\\\\T = (75)/(10)\\\\T = 7.5 seconds`

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Best Regards

'Borz'