Question

I need help with these questions :
(see image )
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Answer 1

Hey There!

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Answer:

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DATA:

Angle of projection = θ(theta) =
`30^0`

Initial Velocity =
`V_0` =
`2x10^3`

Acceleration due to gravity = g = 9.8 m/s^2

Vertical Velocity =
`V_Y` = ?

Horizontal Velocity =
`V_X` = ?

Range of the Shell = R = ?

Maximum Height = H = ?

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SOLUTION:

Vertical Velocity is given by,

`V_Y = V_0Cos`θ

`V_Y = (2x10^3)xCos(30)`

`V_Y = (2x10)^3x(0.866)\\\\V_Y = 1732.05 (m)/(s)`

Horizontal Velocity is given by,

`V_X = V_0Sin`θ

`V_X = (2x10^3)xSin(30)\\\\V_X = (2000)x(0.5)\\\\V_X = 1000(m)/(s)`

Range is given by,

R =
`(V_0^2)/(g)` Sin2θ

`R = ((2x10^3)^2)/(10) x Sin(60)\\\\R = (4x10^6)/(10) x 0.866\\\\R= (4x10^5) x 0.866\\\\R = 346410.16 m`

Horizontal Velocity is given by,

`H = (V_0^2Sin^2(theta))/(2g)\\\\\\H= ((2x10^3)^2xSin(30)^2)/(2x10)\\\\\\H= ((4x10^6)x(0.25))/(20) \\\\H = 50000 m` _____________________________________

Best Regards,

'Borz'