Question

John and Jack divided their math homework. John solved twice as many questions as Jack, plus one problem. How many problems did each boy solve if their were 28 problems?

Answer 1

Explanation:

let jack solved problem = x

so, John solved = 2x+ 1

according to question

x + 2x +1 = 28

3x + 1 = 28

3x = 27

x = 9

Jack solved = x = 9

John solved = 2x+1 = 18+1 = 19

Answer 2

Jack solved 9 probelms

John solved 21 probelms

To solve this problem we can make some equations

John = JO

Jack = JA

JO = 2JA + 1

JA + JO + 28

since we have two equations we can just substitute in the value for JO and solve.

JA + 2JA + 1 = 28

3JA = 27

JA = 9

Then we can check our answer

19 = 2(9) + 1 this is true

9 + 19 = 28. also true.