115k views
6 votes
What is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15, -5)?

User Gubbi
by
3.9k points

1 Answer

3 votes

Perpendicular lines have slopes that are negative reciprocals, so the slope of the line we want to find is -5/3.

Substituting into point-slope form,


y+5=-(5)/(3)(x-15)\\\\y+5=-(5)/(3)x+25\\\\\boxed{y=-(5)/(3)x+20}

User Repeatdomiau
by
5.1k points