Question

What is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15, -5)?

Answer 1

Perpendicular lines have slopes that are negative reciprocals, so the slope of the line we want to find is -5/3.

Substituting into point-slope form,

`y+5=-(5)/(3)(x-15)\\\\y+5=-(5)/(3)x+25\\\\\boxed{y=-(5)/(3)x+20}`