142k views
2 votes
Multiply the polynomials. (3x^2-4x)(2x^3+3x-1)

Multiply the polynomials. (3x^2-4x)(2x^3+3x-1)-example-1

1 Answer

3 votes

Answer:

6x^5 - 8x^4 + 9x^3 - 15x^2 + 4x

Explanation:

(3x^2 - 4x)(2x^3 + 3x - 1)

Multiply the second parentheses by each term from the first parentheses

3x^2(2x^3 + 3x - 1) -4x(2x^3 + 3x - 1)

Distribute 3x^2 through the first parentheses

6x^5 + 9x^3 - 3x^2

then distribute -4x through the second parentheses

-8x^4 -12x^2 + 4x

put them together

6x^5 + 9x^3 - 3x^2 - 8x^4 -12x^2 + 4x

combine the bolded like terms above

6x^5 + 9x^3 - 15x^2 - 8x^4 + 4x

use the commutative property to reorder the terms.

6x^5 - 8x^4 + 9x^3 - 15x^2 +4x

User Davidsun
by
4.8k points