Question

Samreen's brother is 8 years younger than three times her
age. The sum of their ages is 32.

Answer 1

Answer:
Samreen’s age is 10
Samreen’s brother’s age is 22

Step-by-step explanation:
Let s be equal to Samreen’s age.
Let b be equal to Samreen’s brother’s age.

3s-8=b
s+b=32

Substitute the first equation into the second as b
s+b=32
s+(3s-8)=32
Open up the parentheses
s+3s-8=32
4s-8=32
Add 8 to both sides
4s-8+8=32+8
4s=40
Divide both sides by 4 to isolate s
4s/4=40/4
s=10

Therefore, Samreen’s age is 10.

To find Samreen’s brother’s age, we substitute 10 into either of our original equations and solve for b.

s+b=32
10+b=32
Subtract both sides by 10
10+b=32-10
b=22

Therefore, Samreen’s brother’s age is 22.

I hope this helps! Please comment if you have any questions :)