Answer:
Part 1)
![=12a^5-6a^4-5a^3-24a^2+12a-7](https://img.qammunity.org/2021/formulas/mathematics/college/j05tn6vnpo5t9xut4vqgf52hfrx86nnvg1.png)
Part 2)
![(2x^3-10x^2+5x+14)/(x-2)=2x^2-6x-7](https://img.qammunity.org/2021/formulas/mathematics/college/tehi545p53g5p35iaaiip40u5ogb3h2j1i.png)
Explanation:
Part 1)
We would like to multiply:
![(3a^3-2a-7)(4a^2-2a+1)](https://img.qammunity.org/2021/formulas/mathematics/college/7knx9xvpk07di10kb1fa83ie4ud74i41it.png)
Distribute each term from the first group into the second group. So:
![=3a^3(4a^2-2a+1)-2a(4a^2-2a+1)-7(4a^2-2a+1)](https://img.qammunity.org/2021/formulas/mathematics/college/k987qt9barpsyw005cxs9x259rdkvqvm3x.png)
Distribute further:
![=(12a^5-6a^4+3a^3)+(-8a^3+4a^2-2a)+(-28a^2+14a-7)](https://img.qammunity.org/2021/formulas/mathematics/college/qs5vajph005ufur8nyc7jbtcmiifm8gk5s.png)
Combine like terms:
![=(12a^5)+(-6a^4)+(3a^3-8a^3)+(-28a^2+4a^2)+(-2a+14a)+(-7)](https://img.qammunity.org/2021/formulas/mathematics/college/7uxgqxp1wvr4jl43pm6w39o6kuqk9fzo35.png)
Simplify:
![=12a^5-6a^4-5a^3-24a^2+12a-7](https://img.qammunity.org/2021/formulas/mathematics/college/j05tn6vnpo5t9xut4vqgf52hfrx86nnvg1.png)
Part 2)
We would like to divide:
![(2x^3-10x^2+5x+14)/(x-2)](https://img.qammunity.org/2021/formulas/mathematics/college/5tgxo497t1n1c24x9zca9j2wjdva6jhib5.png)
Using long division.
Please refer to the attached document.
For the first step, x goes into 2x³ 2x² times. Hence, we multiply our divisor by 2x².
Next, x goes into -6x^2 -6x times. Hence, we multiply our divisor by -6x.
Finally, x goes into -7x -7 times. So, we multiply our divisor by -7 and we simplify.
Therefore: