Question

If the volume of 50.0 L of a gas at 40.0 °C falls to 35.0 L, what is the new temperature of the gas according to Charles' Law?

43.8 K
0447.1K
219.1 K

Answer 1

219.1K

Step-by-step explanation:

T1/V1= T2/V2

Temp for Gas Laws are always in Kelvin

Volume is always Liters

so T2= (T1xV2)/V1

(35Lx313K)/50L=219.1K