Question

A. Express log 96 in terms of log 2 and log 3.

Answer 1

5log2 + log3

Explanation:

Using the rules of logarithms

logx + logy = log(xy)

log
`x^(n)` ⇔ nlogx

Given

log96

Express 96 as a product of its prime factors

96 =
`2^(5)` × 3 , then

log96

= log(
`2^(5)` × 3 )

= log
`2^(5)` + log3

= 5log2 + log3

Answer 2

linear equations

Explanation: