Question

A meteor is falling towards the earth. The mass and the radius of the earth is 6×10^24 kg and 6.4×10^3 km respectively. What is the height of the meteor from the earth surface at which the acceleration due to gravity is 4m/s^2

Answer 1

Step-by-step explanation:

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Answer 2

3600km

Step-by-step explanation:

gravitational constant is the gravitational attraction between any two things

G = gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²

g = acceleration due to gravity = 4 m/s²

M = mass of the earth = 6 × 10²⁴

r = radius of Earth + height of meteor

Since F = mg and F = GMm/r², mg = GMm/r²

g = GM/r²

r² = GM/g

r = √(GM/g)

r = √((6.67 × 10⁻¹¹ Nm²/kg²) × (6 × 10²⁴ kg))/(4 m/s²)) =

1 × 10⁷ m = 1 × 10⁴ km

To calculate the height of the meteor above the earth,

subtract the radius of the earth from the calculated radius.

height of meteor = 1 × 10⁴ km - 6 × 10³ km = 4 × 10³ km

quora Meave Gilchrist

snapsolve

quora