Question

A spring has a spring constant of 105 N/m. If you compress the spring of 0.1 m past it’s natural length, what force does the spring apply

Answer 1

Heya!!

For calculate force, lets applicate Hooke's law:

`\boxed{F=k * x}`

Δ Being Δ

F = Force = ?

k = Constant = 105 N/m

x = Elongation = 0,1 m

⇒ Let's replace according the formula:

`\boxed{F=105\ N/m * 0,1\ m}`

⇒ Resolving

`\boxed{F = 10,5 \ N }`

Result:

The force is 10,5 Newtons (N).

Good Luck!!