Question

Find three consecutive odd integers whose sum is-213.

Answer 1

first odd number be x = - 73

second odd number be x + 2 = (- 73 + 2) = - 71

third odd number be x + 4 = (- 73 + 4) = - 69

Explanation:

let the first odd number be x

second odd number be x + 2

third odd number be x + 4

Now, three consecutive odd integers whose sum is - 213.

i.e.,

(x) + (x + 2) + (x + 4) = - 213

Then,

(x) + (x + 2) + (x + 4) = - 213

x + x + 2 + x + 4 = - 213

3x + 6 = - 213

3x = - 213 - 6

3x = - 219

x = - 219/3

x = - 73

Thus, The value of x is - 73

Here,

first odd number be x = - 73

second odd number be x + 2 = (- 73 + 2) = - 71

third odd number be x + 4 = (- 73 + 4) = - 69

So

(x) + (x + 2) + (x + 4) = - 213

(- 73) + (- 73 + 2) + (- 73 + 4) = - 213

(- 73) + (- 71) + (- 69) = - 213

- 73 - 71 - 69 = - 213

- 213 = - 213

Hence, L.H.S = R.H.S

-TheUnknownScientist

Answer 2

x + x + 2 + x + 4 = -213
3x + 6 = -213
3x = -219
x = -73
-73 + 2 = -71
-73 + 4 = -69
Solution: -73, -71, -69