Question

Write the Equation of the line that has a slope of 3/4 and passes through the point (-6,8)

Answer 1

`\boxed{4y - 3x = 50}`

.

Explanation:

User the form below

`\boxed{\boxed{y-y_1 = m(x - x_1)}}`

Where

• 
  `m` is a slope
• 
  `(x_1,~y_1)` is point of the line

.

So, the equation is

`m = (3)/(4)`

`(-6,~8)\to x_1 = -6~~and~~y_1 = 8`

.

`y-y_1 = m(x - x_1)`

`y - 8 = (3)/(4) (x - (-6))`

`4(y - 8) = 3(x + 6)`

`4y - 32 = 3x + 18`

`4y - 3x = 18 + 32`

`4y - 3x = 50`

.

Happy to help :)