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Help me please, geometry

Help me please, geometry-example-1
User Moszi
by
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1 Answer

9 votes

Answer:

x = 19.5 (nearest tenth)

Explanation:

Trigonometric ratios


\sf \sin(\theta)=(O)/(H)\quad\cos(\theta)=(A)/(H)\quad\tan(\theta)=(O)/(A)

where:


\theta is the angle

  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Use the cos ratio to find the measure of the altitude (the perpendicular drawn from the vertex of the triangle to the opposite side):


\implies \cos(47^(\circ))=(a)/(18)


\implies a=18\cos(47^(\circ))

Now use the sin ratio to the the measure of side x:


\implies \sin(39^(\circ))=(a)/(x)


\implies x=(a)/(\sin(39^(\circ)))


\implies x=(18\cos(47^(\circ)))/(\sin(39^(\circ)))


\implies x=19.50671018

Therefore, x = 19.5 (nearest tenth)

User Johannchopin
by
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