Question

Alejandro made an error in the steps below when determining the equation of the line that is perpendicular to the line 4x – 3y = –8 and passes through the point (3, –2).

Answer 1

y=-3/4x+1/4

Explanation:

This is the concept of equations of graphs; We are required to calculate for the equation if the line that is perpendicular to the line 4x-3y=-8 and passes through point (3,-2).

Here we proceed as follows;

4x-3y=-8 can be written in he form y=mx+c as follows;

-3y=-4x-8

thus;

y=4/3x+8/3

The slope of the line perpendicular to this is -3/4. Thus using point (3,-2) the equation will be as follows;

-3/4=(y--2)/(x-3)

-3/4(x-3)=y+2

y+2=-3/4(x-3)

y+2=-3/4x+9/4

thus;

y=-3/4x+1/4

the answer is:

y=-3/4x+1/4