Answer:
B, a double root
Explanation:
for a quadratic equation ax²+bx+c=0,
we define the discriminant as:
D=b²-4ac
if D=0, we have a double root
if D>0, we have real roots (is D is a square of an integer, they are also rational
if D<0, we get non-real roots.
this derives from the formula to solve the equation, where D appears in a root:
X1,2= (-b±sqrt(D))/a
in the given equation, a=1, b=-4, c=4, so we get:
D = (-4)²-4×1×4 = 0
hence the answer is B