106k views
5 votes
The length of a rectangle is 5 m more than twice the width, and the area of the rectangle is 63 m². Find the dimensions of the rectangle.

Length=

Width =

The length of a rectangle is 5 m more than twice the width, and the area of the rectangle-example-1
User Avysk
by
8.1k points

1 Answer

13 votes

Answer:

width = 9/2 m

length = 14 m

Explanation:

Let width = x

If the length of a rectangle is 5 m more than twice the width:

⇒ length = 2x + 5

Use the given information to create a quadratic equation:

Area of a rectangle = width × length

⇒ 63 = x(2x + 5)

⇒ 63 = 2x² + 5x

⇒ 2x² + 5x - 63 = 0

Find the value of x by factorizing the quadratic:

⇒ 2x² + 5x - 63 = 0

⇒ 2x² + 5x - 63 = 0

⇒ 2x² + 14x - 9x - 63 = 0

⇒ 2x(x + 7) - 9(x + 7) = 0

⇒ (2x - 9)(x + 7) = 0

Therefore:

⇒ (2x - 9) = 0 ⇒ x = 9/2

⇒ (x + 7) = 0 ⇒ x = -7

Width cannot be negative, therefore, x = 9/2 only

⇒ width = 9/2 m

⇒ length = 2(9/2) + 5 = 14 m

User Kevin Jose
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories