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1 vote
Given h(x) = 5x + 2, solve for 2 when h(x) = -8.

1 Answer

5 votes

Answer:


\huge\boxed{\sf x = -2}

Explanation:


\sf h(x) = 5x+2\\\\Put \ h(x) = -8\\\\-8 = 5x+2\\\\Subtract \ 2 \ to \ both \ sides\\\\-8-2 = 5x\\\\-10 = 5x\\\\Divide\ both \ sides \ by \ 5\\\\-10 / 5 = x \\\\x = -2 \\\\\rule[225]{225}{2}

Hope this helped!

~AH1807

User Mario Inostroza
by
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