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Find the nth term of the following sequence: 4 7 12 19 28

User Collin Krawll
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1 Answer

11 votes
11 votes

Answer:

n²+3

Step-by-step explanation:

The differences between the terms are not the same, so this is not "linear". Knowing that the sequence may have started with a 1, you can try subtracting the first number with a number to get 1, and use that number to subtract the rest.

4 - 3 = 1
7 - 3 = 4
12 - 3 = 9
19 - 3 = 16
28 - 3 = 25

In this case, subtracting 3 to all the numbers gave us perfect squares! So this means the nth term has to do with squaring the number and adding three afterward! This can be checked.

√1 = 1
√4 = 2
√9 = 3
√16 = 4
√25 = 5

As we found the values of these terms by subtracting three first and then finding its square root, the nth term will be the opposite; squaring and then adding three! Again, this can be checked!

1² + 3 = 4
2² + 3 = 7
3² + 3 = 12
4² + 3 = 19
5² + 3 = 28

Hope this helps !! :D

User Vivex
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