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5 votes
Eliminate the parameter “t” for the parametric equations, where 0 < t < 5.

x = √5t

y = 2t — 2


Answers:

A) y = 2/5x^2 — 2
B) y = 5/2X^2 — 5
C) y = 2√5x — 2
D) y = 2/5x^2 — 2

User Exoddus
by
4.9k points

1 Answer

3 votes

Answer:

A) y = 2/5x^2 — 2

Explanation:

We are given the parametric equation:


x=√(5t)


y=2t-2

To express y in terms of x, we solve for t in the first equation and substitute in the second equation.

Squaring:


x^2=(√(5t))^2


x^2=5t

Solving for t:


\displaystyle t=(x^2)/(5)

Substituting in the second parametric equation:


\displaystyle y=2(x^2)/(5)-2


\displaystyle y=(2)/(5)x^2-2

Correct choice: A) y = 2/5x^2 — 2

User Tarandeep Singh
by
5.2k points
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