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The coordinates of the vertices of triangle ABC are A(3,6), B(6, 3), and C(9, 9). If triangle ABC Is dilated by 1/3x and 1/3y to create triangle A'B'C', which set of coordinates represents the vertices of triangle ABC?



User TechiRik
by
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1 Answer

6 votes

Answer:


A' = (1,2)


B'=(2,1)


C' =(3,3)

Explanation:

Given


A = (3,6)


B = (6,3)


C = (9,9)


Scale = (1)/(3)

Required

Determine the vertices of ABC

If truly the question asks for the vertices of ABC, then the vertices are:


A = (3,6)
B = (6,3)
C = (9,9)

However, I'm quite sure that's not the requirement of the question. So, I'll solve for A'B'C'

To do this, we simply multiply the vertices of ABC by the scale of dilation.


(A'B'C') = Scale\ Factor * (ABC)


A' = (1)/(3) * A


A' = (1)/(3) * (3,6)


A' = ((3)/(3),(6)/(3))


A' = (1,2)


B' = (1)/(3) * B


B' = (1)/(3) * (6,3)


B' = ((6)/(3),(3)/(3))


B'=(2,1)


C' = (1)/(3) * C


C' = (1)/(3) * (9,9)


C' = ((9)/(3),(9)/(3))


C' =(3,3)

User Animesh Manglik
by
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