Question

1.792 x 10^(-22) in standard form

Answer 1

108g

Step-by-step explanation:

Weight of the atom of an element = 1.792x10-22 (Given)

Let the atomic mass of the atom be = x

x ms of the element contains Avogadro number of atoms = 6 × 10^23 atoms

Weight of one mole of atoms = atomic weight

Where one mole = 6.022 × 10^23 atoms

Weight of one atom = x/(6 × 10^23)

= 1.8 × 10^-22

Thus, the atomic weight will be -

x = 6 × 10^23 × 1.8 × 10^-22​ = 107.9 = 108 g

/mole

Therefore, the atomic mass of the element is 108 g/mole.

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