Answer:
20ft by 40ft
Explanation:
The area of the fence is 800 ft². Let x represent one side of the fence and y the other side of the fence, hence:
xy = 800 (1)
The cost of fencing (C) is:
C = 3x + x + y + y
C = 4x + 2y (2)
From xy = 800, y = 800/x. Substituting in equation 2:
![C = 4x +2( (800)/(x))\\\\Minimum \ cost\ is\ at\ C'=0\\\\Hence:\\ \\C'=4-(1600)/(x^2) \\\\4-(1600)/(x^2) =0\\\\4=(1600)/(x^2) \\\\x=\sqrt{(1600)/(4) } \\\\x=20\ ft\\\\y=(800)/(x) =(800)/(20)=40\ ft](https://img.qammunity.org/2021/formulas/mathematics/college/jw7yc763vkh074dyl1mvyhx3f726k0alto.png)