Question

Jeff hiked to the top of mt whitney from the trail head a distance of 14 miles. Jon after camping overnight on the trail hiked only 12 miles to the top of mt whitney. If jeff and jon were both hiking for the same amount of time, and jon hiked 1mph slower then jeff how fast did each man hime

Answer 1

Jeff’s speed is 7 mph

Jon’s speed is 6 mph

Explanation:

Since the time spent by each is same, let us call the number of hours x

Mathematically;

Time = distance/speed

Let us call Jeff’s speed y

x = 14/y ••••••(i)

For Jon

he hiked 1 mph slower, so his speed will be (y-1) mph

x = 12/(y-1)

Since x is equal in both cases

14/y = 12/y-1

14(y-1) = 12y

14y -14 = 12y

14y-12y = 14

2y = 14

y = 14/2

y = 7 mph

Jon is 1 mph slower which is 7-1 = 6 mph