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In the standard (x,y) coordinate plane, what is the midpoint of the line segment that has endpoint a (3,8) and (1,-4)?

The answer is (2, 2) but how do I solve?

1 Answer

4 votes

Answer:


M = (2,2)

Explanation:

Given


(3,8) and
(1,-4)

Required

Determine the coordinate of the midpoint (M)

This is calculated as thus:


M = (1)/(2)(x_1 + x_2, y_1 + y_2)

Where


(3,8) --
(x_1,y_1)


(1,-4) --
(x_2,y_2)

So, we have:


M = (1)/(2)(3 + 1, 8 - 4)


M = (1)/(2)(4, 4)


M = ((1)/(2)*4, (1)/(2)*4)


M = (2,2)

Hence, the coordinates of the midpoint is (2,2)

User Krzak
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