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Let sin(2x) = cos(x), where 0° ≤ x < 180°. What are the possible values for x?

User Ed Staub
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2 Answers

4 votes

Answer:

For those too lazy to read answer above, it's D.

Explanation:

Edge2021

User Deani Hansen
by
8.4k points
4 votes

Answer:

The possible values of x are 90°, 30° and 150°.

Explanation:

Given that,

sin(2x) = cos(x) where 0° ≤ x < 180°

We know that, sin(2x) = 2 sinx cosx

2 sinx cosx = cosx

Subtract cosx on both sides

2 sinx cosx - cosx = 0

cosx (2sinx-1)=0

It means, cosx = 0 and (2sin x -1 ) = 0

cos x = cos0 and sinx = 1/2

x = 90° and x = 30°, 150°

Hence, the possible values of x are 90°, 30° and 150°.

User AvisSiva
by
7.6k points

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