V1 - 2 sin cos 0 = cos 0 - sin

asked Nov 4, 2021 233k views

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$√(1 - 2sin θ \cosθ ) = \sqrt{ {sin}^(2) θ + {cos}^(2)θ - 2 sinθcosθ } = \sqrt{ {(cosθ - sinθ) }^(2) } = cosθ - sinθ$

Gyurisc answered Nov 8, 2021

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