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Find the vertex, focus, directrix, and axis of symmetry of the parabola. (y-3)^2 =-6(x+1)

Find the vertex, focus, directrix, and axis of symmetry of the parabola. (y-3)^2 =-6(x+1)
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Find the vertex, focus, directrix, and axis of symmetry of the parabola.
(y-3)^2 =-6(x+1)

User Andrew Leedham
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Answer:

This is my solution for your question

Find the vertex, focus, directrix, and axis of symmetry of the parabola. (y-3)^2 =-6(x-example-1
User Elham
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