Answer:
(1 / cot²θ) + secθ cosθ
(1 / cotθ) == tanθ
Therefore
tan²θ + secθ cosθ
secθ == (1 / cos θ)
tan²θ + (1 / cosθ) cosθ
The cosθ 's cancel out
tan²θ + 1
tan²θ + 1 == sec²θ
sec²θ is the simplified answer
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