Question

Write the equation of a circle with endpoints of the diameter are (-8, 1) and (4,5)

Answer 1

centre of the circle =Midpoint of the diameter

centre of the circle=

`( ( - 8 + 4)/(2) , (5 + 1)/(2) ) = ( - 2 ,3)`

radius of the circle=

`\sqrt{(4 - ( - 2) ^(2) + (5 - 3 )^(2) } = √(36 + 4) = √(40 ) = 2 √(10) </p><p>`

equation of the circle: (x+2)²+(y-3)² = 40

ie.. x²+4x+4+ y²- 6y+ 9=40

ie... x²+y²+4x-6y-27=0

this is the answer......