82.3k views
13 votes
L

N
(x-4) in. O
(x-3) in.
(x + 2) in.
x in.
K
Which value of x would make NO || KJ?
1
6
08
O 10

L N (x-4) in. O (x-3) in. (x + 2) in. x in. K Which value of x would make NO || KJ-example-1

1 Answer

6 votes

Answer:

x = 8

Explanation:


\sf If\:\: \overline{NO} \parallel \overline{KJ}\:\:then\:\: \triangle LNO \sim\triangle LKJ

Therefore:


\implies \sf \overline{LN} : \overline{LO} = \overline{LK} : \overline{LJ}


\implies (x-3):(x-4)=(x-3)+(x+2):(x-4)+x


\implies (x-3)/(x-4)=(2x-1)/(2x-4)


\implies (x-3)(2x-4)=(2x-1)(x-4)


\implies 2x^2-10x+12=2x^2-9x+4


\implies -10x+12=-9x+4


\implies 12=x+4


\implies x=8

User DarylChymko
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories