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A carnival ride has cars that each hold 4 44 adult passengers. The weights of the passengers for this ride are normally distributed with a mean of 65 kg 65kg65, start text, k, g, end text and a standard deviation of 12 kg 12kg12, start text, k, g, end text. Assume that the weights of passengers are independent from each other. Let T = T=T, equals the total weight of 4 44 randomly selected adult passengers for this ride. Find the probability that the total weight exceeds 290 kg 290kg290, start text, k, g, end text. You may round your answer to two decimal places.

User Msencenb
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2 Answers

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Final answer:

To find the probability that the total weight exceeds 290kg for 44 randomly selected adult passengers, calculate the z-score for 290kg and use a standard normal distribution table or calculator to find the probability, which will be extremely close to zero.

Step-by-step explanation:

To find the probability that the total weight exceeds 290kg for 44 randomly selected adult passengers, we need to calculate the z-score for 290kg using the given mean and standard deviation. The z-score formula is z = (x - μ) / σ, where x is the value you want to find the z-score for, μ is the mean, and σ is the standard deviation. Once we have the z-score, we can use a standard normal distribution table or a calculator to find the probability.

Using the given information, the z-score for 290kg can be calculated as z = (290 - 65) / 12 = 171 / 12 = 14.25.

Now, we can use a standard normal distribution table or a calculator to find the probability corresponding to a z-score of 14.25. The probability is extremely close to zero, indicating that the likelihood of the total weight exceeding 290kg is very low.

User AhmadReza Payan
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3 votes

Answer: Correct answer is .11

Step-by-step explanation:

User FLY
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