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If a rectangle is (x^2+18x+81) square inches and the length is (x+9) inches what is the width

User Nexevis
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1 Answer

5 votes

Answer:

Explanation:

x^2 + 18x + 81 = (x + 9)(x + 9)

The figure is a square

Area = (x + 9)(x + 9)

Length = x + 9

L*W = Area

(x + 9)*w = (x + 9) (x + 9)

divide by x + 9

w = ((x + 9)(x+9)) / ( x + 9) one of the x + 9 s cancel

w = x + 9

Since the L = w, the figure is a square.

User Joakimja
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