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What is the equation of the quadratic graph with a focus of (3, -1) and a directrix of y = 1?

2 Answers

5 votes

Answer: f(x) = (x - 3)²

Explanation:

User Shachar
by
5.0k points
2 votes

Answer:

The equation of the quadratic graph is y =
-(1)/(4) (x - 3)²

Explanation:

The standard form of the equation of the quadratic graph is

(x - h)² = 4p(y - k), where

  • The vertex of the parabola is (h, k)
  • The focus is (h, k + p)
  • The directrix is at y = k - p

∵ The focus is (3, -1)

∵ The focus is (h, k + p)

→ Compare them

h = 3

k + p = -1 ⇒ (1)

∵ The directrix is at y = 1

∵ The directrix is at y = k - p

→ Compare them

k - p = 1 ⇒ (2)

→ Add equations (1) and (2) to eliminate p

∵ (k + k) + (p - p) = (-1 + 1)

∴ 2k + 0 = 0

∴ 2k = 0

→ Divide both sides by 2

K = 0

→ Substitute the value of k in equation (1) to find p

∵ 0 + p = -1

p = -1

→ Substitute the values of h, k, and p in the form of the equation above

(x - 3)² = 4(-1)(y - 0)

∴ (x - 3)² = -4(y)

(x - 3)² = -4y

→ Divide both sides by -4


-(1)/(4) (x - 3)² = y

→ Switch the two sides

y =
-(1)/(4) (x - 3)²

The equation of the quadratic graph is y =
-(1)/(4) (x - 3)²

User Mhdjazmati
by
4.2k points