Answer:
The perpendicular line to y=2/3x+2 and passes through the point (3,4) is y = -3/2x - 1/2
Explanation:
A line perpendicular to another has a slope that is the negative reciprocal of the slope of the other line.
so for the y=2/3x+2,
the slope is 2/3, the negative reciprocal is,
- 3/2 (new slope)
y = mx + b
y = (-3/2)x + b
plug in the point (3,4):
(4) = (-3/2)(3) + b
(4) = (-9/2) + b
(4) + (-9/2) = (-9/2) + (-9/2) + b
- 1 / 2 = b
y = (-3/2)x - 1/2
Let me know if you have any questions!