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Approximating slopes of tangent lines using the process shown last week for the function

f(x) =3-x2 at the point (2, -1). Using a straightedge, draw a tangent line as accurately as possible at
the point (2, -1). Then draw a secant line through the points (2, -1) and (3, -6). We will refer to that as the right secant line. Draw another secant line, this time through the points (1, 2) and (2, -1). This is the left secant line. Answer the following questions.
2. What is the slope of the right secant line?

User Basak
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Answer:

-5

Explanation:

The right secant line has a "rise" of -6-(-1) = -5 for a "run" of 3-2 = 1. The slope is the ratio ...

m = rise/run = -5/1 = -5

The slope of the right secant line is -5.

Approximating slopes of tangent lines using the process shown last week for the function-example-1
User EldenChris
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