Question

G(x) = x^4-32x^2+256; x=-4

Answer 1

g(-4) = 0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Function Notation

Explanation:

Step 1: Define

g(x) = x⁴ - 32x² + 256

x = -4

Step 2: Evaluate

1. Substitute: g(-4) = (-4)⁴ - 32(-4)² + 256
2. Exponents: g(-4) = 256 - 32(16) + 256
3. Multiply: g(-4) = 256 - 512 + 256
4. Subtract: g(-4) = -256 + 256
5. Add: g(-4) = 0