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I need help with #5 please I have no idea how to do this

I need help with #5 please I have no idea how to do this-example-1

1 Answer

5 votes

Answer:

tan theta = 3/4

cot theta = 4/3

sin theta = 3/5

csc theta = 5/3

cos theta 4/5

sec theta = 5/4

Explanation:

Since this is a right triangle, we can use trig functions

We know the adjacent side and the opposite side so we will use the tangent function

tan theta = opposite/ adjacent

tan theta = 6/8

tan theta = 3/4

cot theta = adjacent / opposite = 8/6 = 4/3

Now we need to find the hypotenuse, using the pythagorean theorem

a^2 + b^2 = c^2

6^2 + 8^2 = c^2

36+64 = c^2

100 =c^2

Taking the square root

sqrt(100) = sqrt(c^2)

10 = c

The hypotenuse = 10

sin theta = opposite / hypotenuse

sin theta = 6/10 = 3/5

csc theta = hypotenuse / opposite = 10/6 = 5/3

cos theta = adjacent/ hypotenuse = 8/10 = 4/5

sec theta = hypotenuse/adjacent = 10/8 = 5/4

User Sada
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