Question

How do you solve this equation:
`((2-b)^2)/((b-2)^2)`

Answer 1

1

Explanation:

For the top, you can write it as (2-b)^2 = (-1(b-2))^2 = (-1)^2(b-2)^2 = 1(b-2)^2 = (b-2)^2. Putting that back in, we get: ((b-2)^2)/((b-2)^2) = 1 because the top and bottom cancel.

I hope this helps! :)