Question

A food scientist uses a mixture of the gases helium and argon to preserve packaged food. The amount of

each gas the scientist uses for the mixture is modeled by the equation 5.6H + 0.56A = 22.4, where H and A
are the masses, in grams, of helium and argon, respectively. If the scientist uses 10 grams of argon, how
many grams of helium are used?
Answer:

Answer 1

9514 1404 393

Answer:

3 grams of helium are used

Explanation:

Solving the given equation for H, we have ...

5.6H +0.56A = 22.4

5.6H = 22.4 -0.56A

H = (22.4 -0.56A)/5.6

H = 4 -0.1A

Using A=10, we find ...

H = 4 -0.1·10 = 3

3 grams of helium are used.