Question

The area A of a trapezoid with parallel sides of lengths A andB and height H is a=1/2(a+b)h

Answer 1

last option, 2A / (a + b) = h

Explanation:

Answer 2

`\sf D)\ (2A)/(a+b)=h\ \ \textsf{or}\ \ 2A/(a+b)=h`

Explanation:

Given: A = ½(a + b)h

We need to solve for h.

1. Rewrite the equation:

`\sf A=(1)/(2)(a+b)h \implies A=(1)/(2)h(a+b)`

2. Divide both sides by (a + b):

`\sf \\\implies (A)/(a+b)=((1)/(2)h(a+b))/(a+b)\\\\\implies (A)/(a+b)=(1)/(2)h`

3. Multiply both sides by 2:

`\sf \\\implies 2\left((A)/(a+b)\right)=2\left((1)/(2)h\right)\\\\\implies (2A)/(a+b)=h\ \ \textsf{or}\ \ 2A/(a+b)=h`