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Write down the first 4 terms in the expansion of (1+2x)^7 ​

User Pyae Sone
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2 Answers

5 votes

Answer:

1 + 14x + 84x^2 + 280x^3 or

128x^7 + 448x^6 + 672x^5 + 560x^4.

(see explanation),

Explanation:

They are 1^7 + 7C1 1^(7-1)(2x) + 7C2 1^5 (2x)^2 + 7C3 1^4 (2x)^3

= 1 + 14x + 21* 4x^2 + 35*8x^3

= 1 + 14x + 84x^2 + 280x^3

If you require the answer in descending degrees of x by a similar method the answer is:

128x^7 + 448x^6 + 672x^5 + 560x^4.

User Panktijk
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6 votes
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