Question

Can someone explain to me how i do this and tell me the equation

Answer 1

The equation of line in slope-intercept form is:

`y=2x+(-4)`

Explanation:

Given the two points

• (0, -4)

• (3, 2)

slope between (0, -4) and (3, 2)

`\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)`

`\left(x_1,\:y_1\right)=\left(0,\:-4\right),\:\left(x_2,\:y_2\right)=\left(3,\:2\right)`

`m=(2-\left(-4\right))/(3-0)`

`m=2`

We know that the y-intercept can be determined by setting x=0, and solving for y.

From the graph, it is clear that

at x=0, y=-4

Thus, the value of y-intercept (b) = -4

We also know that the slope-intercept form of the line equation is

`y=mx+b`

where m is the slope and b is the y-intercept

substituting m=2 and b=-4 in the intercept form

`y=mx+b`

`y=2x+(-4)`

Thus, the equation of line in slope-intercept form is:

`y=2x+(-4)`