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Suppose IQ scores were obtained for 20 randomly selected sets of twins. The 20 pairs of measurements yield x overbarequals103.26​, y overbarequals102.05​, requals0.897​, ​P-valueequals​0.000, and ModifyingAbove y with caret equals negative 13.47 plus 1.12 x​, where x represents the IQ score of the twin born first. Find the best predicted value of ModifyingAbove y with caret given that the twin born first has an IQ of 105​? Use a significance level of 0.05.

1 Answer

6 votes

Answer

The value is
P = 131.07

Step -by -step -explanation :

From the question we are old that

The sample size is n = 20

The sample mean for the first person of each twin is
\= x = 100.45

The sample mean for the second person of each twin is
\= y = 103

The correlation between both data is r = 0.908

The p-value is p-value = 0.000

The equation
\^ y = 13.47 + 1.12 x

Here we are told that x represents the first person to be given birth to among each twin

The value of x considered is x = 105

Generally given that p-value = 0.000

Then the Predicted value of
\^ y is mathematically represented as


P = 13.47 + 1.12 (105)

=>
P = 131.07

User Mark R Lindsey
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