7.0k views
1 vote
Consider the matrices. Help with 3 math questions.

Consider the matrices. Help with 3 math questions.-example-1
Consider the matrices. Help with 3 math questions.-example-1
Consider the matrices. Help with 3 math questions.-example-2
Consider the matrices. Help with 3 math questions.-example-3

1 Answer

1 vote

Answer:


A-B = \begin {bmatrix} - 7 & 7 \\ - 10 & -2 \\ 10 & - 9 \end{bmatrix} \\


PQ = \begin {bmatrix} -9 & -18\\ -27 & 0\\-45 & -36\\9 & 54 \end{bmatrix}\\

Explanation:


A= \begin {bmatrix} - 2 &amp; 3\\ - 7 &amp; 4\\9 &amp; - 1 \end{bmatrix} \: and \: B \begin {bmatrix} 5 &amp; - 4\\ 3 &amp; 6\\-1 &amp; - 8\end{bmatrix} \\\\</p><p></p><p>A-B = \begin {bmatrix} - 2 &amp; 3\\ - 7 &amp; 4\\9 &amp; - 1 \end{bmatrix} - \begin {bmatrix} 5 &amp; - 4\\ 3 &amp; 6\\-1 &amp; - 8\end{bmatrix} \\\\</p><p></p><p>A-B = \begin {bmatrix} - 2 - 5 &amp; 3-(-4)\\ - 7-3 &amp; 4-6 \\9-(-1) &amp; - 1-8 \end{bmatrix} \\\\</p><p></p><p>A-B = \begin {bmatrix} - 2 - 5 &amp; 3+4\\ - 7-3 &amp; 4-6 \\9+1 &amp; - 1-8 \end{bmatrix} \\\\</p><p></p><p>A-B = \begin {bmatrix} - 7 &amp; 7 \\ - 10 &amp; -2 \\ 10 &amp; - 9 \end{bmatrix} \\\\


P= \begin {bmatrix} 1 &amp; 2\\ 3 &amp; 0\\5 &amp; 4\\-1 &amp; - 6 \end{bmatrix} \: and \: Q= \begin {bmatrix} - 1\\ - 8\end{bmatrix} \\\\</p><p>PQ = \begin {bmatrix} 1 &amp; 2\\ 3 &amp; 0\\5 &amp; 4\\-1 &amp; - 6 \end{bmatrix} \begin {bmatrix} - 1\\ - 8\end{bmatrix} \\\\</p><p></p><p>PQ = \begin {bmatrix} 1(-1)+1(-8) &amp; 2(-1)+2(-8)\\ 3(-1)+3(-8) &amp; 0(-1)+0(-8)\\5(-1)+5(-8) &amp; 4(-1)+4(-8)\\-1(-1)+(-1)(-8) &amp; - 6(-1)+(-6)(-8) \end{bmatrix}\\\\</p><p></p><p>PQ = \begin {bmatrix} - 1-8 &amp; - 2-16\\ - 3-24 &amp; 0+0\\-5-40 &amp; - 4-32\\1+8 &amp; 6+48 \end{bmatrix}\\\\</p><p></p><p>PQ = \begin {bmatrix} -9 &amp; -18\\ -27 &amp; 0\\-45 &amp; -36\\9 &amp; 54 \end{bmatrix}\\\\


S= \begin{bmatrix} 3 &amp; 4\\-1 &amp; - 2\end{bmatrix}\: and \: T =\begin{bmatrix} - 2&amp; 0\\-4 &amp; 5\end{bmatrix}\\\\</p><p></p><p>ST= \begin{bmatrix} 3 &amp; 4\\-1 &amp; - 2\end{bmatrix} \begin{bmatrix} - 2&amp; 0\\-4 &amp; 5\end{bmatrix}\\\\</p><p></p><p>ST= \begin{bmatrix} 3(-2)+4(-4) &amp; 3(0)+4(5)\\-1 (-2)+(-2)(-4)&amp; - 1(0)+(-2)5\end{bmatrix}\\\\</p><p></p><p>ST= \begin{bmatrix} -6-16 &amp; 0+20\\2+8 &amp; 0 - 10\end{bmatrix}\\\\</p><p></p><p>ST= \begin{bmatrix} -22 &amp; 20\\10 &amp; - 10\end{bmatrix}\\

User Levi Rosol
by
4.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.