Answer:
![y+3=-2(x-5)](https://img.qammunity.org/2021/formulas/mathematics/college/74dmks6cbqv8y8tw9jx7wouxicigs35880.png)
Explanation:
We need an equation of the line perpendicular to the given line
![y=(1)/(2)x+4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2kvc02c2qrc2w09ydxxvt142aynn0ew8nt.png)
if we compare this equation with the standard form:
![y=mx+c](https://img.qammunity.org/2021/formulas/mathematics/middle-school/b1v2dukrdfg5c9fzxi2cm7vvu51w62en9p.png)
m equals 1/2 and c=4 , we do not c (y-intercept) in our calculation so just ignore it.
Furthermore the slope of the perpendicular line is given by the formula:
![m_1m_2=-1\\](https://img.qammunity.org/2021/formulas/mathematics/college/y1t3cktgdngkd30iyudksdpvvibfievuv6.png)
where our
and m2 is the slope of the perpendicular line so,
![m_1m_2=-1\\\\(1)/(2) m_2=-1\\\\m_2=-2](https://img.qammunity.org/2021/formulas/mathematics/college/zch1b479h3ot82eufol1fhafqpoy4e12s6.png)
we have the slope of the perpendicular line which is -2 and the point P is given to us which is (5,-3) , so we use the equation of point-slope form:
![y-y_1=m(x-x_1)\\y-(-3)=-2(x-5)\\y+3=-2x+10\\y=-2x+7\\](https://img.qammunity.org/2021/formulas/mathematics/college/eci73l0hqyqjxxumdqovp0diayqsxwesc3.png)
we need our answer in point-slope form so it would be
![y+3=-2(x-5)](https://img.qammunity.org/2021/formulas/mathematics/college/74dmks6cbqv8y8tw9jx7wouxicigs35880.png)