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Find the equation of the line that is perpendicular to the given line and passes through the given point. Enter your answer in slope-intercept form (y = mx + b) with the values of m and b given as decimals, rounded to the nearest hundredth if necessary.

y = 2x ; (5, −5)

The equation is y = .

User Bold Bat
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Answer:

y = -0.50x -2.50

Explanation:

The perpendicular line will have a slope that is the opposite reciprocal of the slope of the given line:

m = -1/2

The given point can be used with this slope in the point-slope equation for a line:

y -k = m(x -h) . . . . . line with slope m through point (h, k)

y +5 = -1/2(x -5)

y = -1/2x +5/2 -5

y = -0.50x -2.50

Find the equation of the line that is perpendicular to the given line and passes through-example-1
User Alex Henrie
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