Question

What is the molarity of a solution made by dissolving 2.42 grams of rubidium chloride in enough water to make a 250.0 mL solution?

Answer 1

M=n/V

n=m/MM

V=250 ml=0.25 L

RbCl

Molar mass: 120.921 g/mol

n=2.42 : 120.921= 0.02

M=0.02/0.25 = 0.08 M