Question

Help!!!!!!!!!!!!!!!!!!

Answer 1

The density of the sample : 0.827 g/L

Further explanation

In general, the gas equation can be written

`\large {\boxed {\bold {PV = nRT}}}`

where

P = pressure, atm , N/m²

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m2, v= m³)

T = temperature, Kelvin

n= 1 mol

MW Neon = 20,1797 g/mol

mass of Neon :

`\tt mass=mol* MW\\\\mass=1* 20,1797 =20.1797~g`

The density of the sample :

`\tt \rho=(m)/(V)\\\\\rho=(20,1797)/(24.4)=0.827~g/L`

or We can use the ideal gas formula ta find density :

`\tt \rho=(P* MW)/(RT)\\\\\rho=(1* 20.1797)/(0.082* 298)\\\\\rho=0.826~g/L`