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A particle with mass of 200 kg is acted on by a net force of 4.5N. The acceleration of the particle is most nearly​
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A particle with mass of 200 kg is acted on by a net force of 4.5N. The acceleration of the particle is most nearly​

User Cstroe
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1 Answer

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A :-) for this question , we should apply
F = ma
Given - m = 200 kg
F = 4.5 N
Solution -
F = ma
4.5 = 200 x a
4.5 by 200 = a
0.0225 = a
a = 0.0225

.:. The acceleration is 0.0225.
User Tino
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